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Hyperbolic Tessellations

David E. Joyce (djoyce@clarku.edu)


The hyperbolic plane has more space in it then the Euclidean plane. There are only three regular tessellations of the Euclidean plane, namely {3,6} in which equilateral triangles meet six at each vertex, {4,4} in which squares meet four at each vertex, and {6,3} in which hexagons meet three at each vertex. But the hyperbolic plane can be tiled by any kind of regular polygon, and in many different ways. If

1/n + 1/k < 1/2,

then {n,k} is a tessellation of the hyperbolic plane by regular n-gons where k of them meet at each vertex. So, for instance, {5,4} is a tiling of the hyperbolic plane by pentagons meeting four at each vertex.

(A notation like {3,6} is called a Schläfli symbol.)

The Poincare Disk

The hyperbolic plane can not be metrically represented in the Euclidean plane, but Poincare described ways that it can be conformally represented in the Euclidean plane. One of those is to represent the hyperbolic plane as the points inside a disk. For this representation, a straight line in the hyperbolic plane is represented as the part (in the disk) of a circle that meets the boundary of the disk at right angles. What this means will be clear in the examples displayed below.

The regular tessellation {5,4} of the hyperbolic plane

A regular tessellation is a covering of the plane by regular polygons so that the same number of polygons meet at each vertex. For instance, here is a representation of the tessellation of the hyperbolic plane by pentagons where four pentagons meet at each vertex, that is, the {5,4}-tessellation.

It may look like the sides of the pentagons are curved, but that's just because of the representation we're using. In the actual hyperbolic plane they would be straight. Also, the pentagon in the middle looks larger, but, again, that's due to the representation. You just can't put an infinite plane in a finite region without a lot of distortion.

The dual tessellation {4,5} of the hyperbolic plane

For a dual tessellation you reverse the roles of the faces and the vertices. The dual of a {5,4} tessellation is a {4,5} tessellation, that is, a tiling by squares, five squares meeting at each vertex. (Here, "square" means regular quadrilateral, a four-sided figure with the same angle at each vertex. It doesn't mean the corners are right-angled, so maybe "square" isn't the best term.) For this picture, the diagonals are drawn so you can see the straight lines that go off to infinity.

Some quasiregular tessellations of the hyperbolic plane

A quasiregular tessellation is built from two kinds of regular polygons so that two of each meet at each vertex, alternately. We'll use the notation quasi-{n,k} to denote a quasiregular tessellation by n-gons and k-gons.

Every regular tessellation {n,k} gives rise to a quasiregular tessellation quasi-{n,k} by connecting the midpoints of the edges of the regular tessellation. In the Euclidean plane there are just two quasiregular tessellations: quasi-{3,6} arises from both {3,6} and {6,3}, while quasi-{4,4} comes from {4,4}. (Of course, quasi-{n,n} is the same as {n,4}.)

Since there are more regular tessellations of the hyperbolic plane than of the Euclidean plane, there are more quasiregular tessellations, too. Here are some of them. First a quasi-{5,4} tessellation. The pentagons are in red or yellow while the squares are in orange. It looks like a plaid disk.

Here's a variation of it where the squares aren't colored, but pentagrams of various colors are placed in the pentagons (the pentagons don't show, either).

A quasi-{3,7} tessellation is built of triangles and heptagons. In the next picture, the triangles are colored a variety of colors while the heptagons are left black.


 



David E. Joyce


August, 1994 Subject:
          Re: Euclid's Elements
    Date:
          Mon, 19 Oct 1998 15:58:24 -0400
   From:
          djoyce@aleph0.clarku.edu (Dave Joyce)
      To:
          david.Boeno@wanadoo.fr

Dear David Boeno,

  I'm very sorry for not replying earlier.
Of course links are welcome, as mentioned on the copyright page.
Furthermore, if you have any need for any image, please feel
free to copy it.

  Sincerely
    Dave Joyce
      Clark University

p.s. I couldn't get anything on the web at perso.wanadoo.fr today.